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If f(x)=(1-sinx)/((pi-2x)^2),when x!=pi...

If `f(x)=(1-sinx)/((pi-2x)^2)`,when `x!=pi/2 ` and `f(pi/2)=lambda,` the `f(x)` will be continuous function at `x=pi/2`,where `lambda=?` (a)`1/8` (b) `1/4` (c) `1/2` (d) none of these

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