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The value of f(0), so that the function...

The value of `f(0),` so that the function `f(x)=((27-2x)^(1/3)-3)/(9-3(243+5x)^(1//5))(x!=0)` is continuous, is given by (a)`2/3` (b) 6 (c) 2 (d) 4

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To find the value of \( f(0) \) such that the function \[ f(x) = \frac{(27 - 2x)^{1/3} - 3}{9 - 3(243 + 5x)^{1/5}} \quad (x \neq 0) \] is continuous, we need to ensure that ...
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