Find the equations of the tangents drawn to the curve `y^2-2x^2-4y+8=0.` from point `(1,2)`

Explanation

To find the equations of the tangents drawn to the curve \( y^2 - 2x^2 - 4y + 8 = 0 \) from the point \( (1, 2) \), we will follow these steps:

### Step 1: Rewrite the curve equation
The given curve is:
\[ y^2 - 2x^2 - 4y + 8 = 0 \]

### Step 2: Differentiate the curve
We will differentiate the equation with respect to \( x \):
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