Find the points on the curve `y=x^3-2x^2-x` at which the tangent lines are parallel to the line `y=3x-2`

Explanation

To find the points on the curve \( y = x^3 - 2x^2 - x \) where the tangent lines are parallel to the line \( y = 3x - 2 \), we can follow these steps:

### Step 1: Find the slope of the given line
The equation of the line is \( y = 3x - 2 \). The slope (m) of this line is 3.

### Step 2: Differentiate the curve
We need to find the derivative of the curve \( y = x^3 - 2x^2 - x \) to determine the slope of the tangent line at any point on the curve.
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