Prove that the general solution of `sin θ= sin α,` is given by : `theta=npi+(-1)^nalpha,n in Zdot`

Explanation

To prove that the general solution of \( \sin \theta = \sin \alpha \) is given by \( \theta = n\pi + (-1)^n \alpha \), where \( n \in \mathbb{Z} \), we can follow these steps:

### Step 1: Rewrite the Equation
Start with the equation:
\[ \sin \theta = \sin \alpha \]

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