The number of values of `x` in the interval `0,5pi`satisfying the equation `3sin^2x-7sinx+2=0` is `0` (b) `5` (c) `6` (d) `10`

Explanation

To solve the equation \(3\sin^2 x - 7\sin x + 2 = 0\) and find the number of values of \(x\) in the interval \(0\) to \(5\pi\), we will follow these steps:

### Step 1: Rewrite the equation
The given equation is a quadratic in terms of \(\sin x\). We can rewrite it as:
\[ 3\sin^2 x - 7\sin x + 2 = 0 \]

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