If `alphaa n dbeta` are the solutions of `acostheta+bsintheta=c ,` then show that `"cos"(alpha+beta)=(a^2-b^2)/(a^2+b^2)` (ii) `cos(alpha-beta)=(2c^2-(a^2+b^2))/(a^2+b^2)`

Explanation

To solve the problem, we need to prove two identities involving the angles α and β, which are the solutions of the equation \( a \cos \theta + b \sin \theta = c \).

### Step 1: Start with the given equation
We know that:
\[ a \cos \theta + b \sin \theta = c \]
This can be rearranged to express \( a \cos \theta \):
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