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Find the maximum and minimum values of the following expressions. (i) `3costheta+5sin(theta-pi/6)` (ii) `4sintheta-3costheta+7`

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To find the maximum and minimum values of the given expressions, we will use the properties of trigonometric functions and the concept of combining sine and cosine functions. ### (i) Expression: \( 3\cos\theta + 5\sin\left(\theta - \frac{\pi}{6}\right) \) **Step 1:** Rewrite the expression using the sine subtraction formula. \[ \sin\left(\theta - \frac{\pi}{6}\right) = \sin\theta \cos\frac{\pi}{6} - \cos\theta \sin\frac{\pi}{6} \] ...
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RD SHARMA ENGLISH-TRIGONOMETRIC RATIOS OF COMPOUND ANGLES-All Questions
  1. If tantheta=(sinalpha-cosalpha)/(sinalpha+cosalpha) then show that si...

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  2. Prove that: 1/(sin(x-a)cos(x-b))=(cot(x-a)+"tan"(x-b))/(cos(a-b))

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  3. Find the maximum and minimum values of the following expressions. (i)...

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  4. If sinA=3/5 and cosB=9/41, 0 < A < pi/2 and 0 < B < pi/2 then find the...

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  5. If cos A=4/(5), cosB=12/13 and (3pi)/2 < A, B < 2pi then find the valu...

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  6. Find the values of the following: t a n 15^0 ii. t a n 75^0

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  7. Find the values of the following: (i)tan105^0 ( ii.) tan((13pi)/12)

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  8. Evaluate the following: sin(7pi)/(12)cospi/4-cos(7pi)/(12)sinpi/4

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  9. Evaluate the following: cos(2pi/3)cos(pi/4)-sin(2pi/3)sin(pi/4)

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  10. Prove that: cos(pi/4-A)cos(pi/4-B)-sin(pi/4-A)sin(pi/4-B)="sin"(A+B)

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  11. Prove that: sin(n+1)A sin(n+2)A+cos(n+1)A cos(n+2)A=cos A

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  12. Prove that: cos(pi/4+x)+cos(pi/4-x\ )=sqrt(2)cosx

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  13. Prove that: cos((3pi)/4+x)-cos((3pi)/4-x\ )=sqrt(2)sinx

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  14. Prove that: sin(x+y)/sin(x-y)=(tanx+tany)/(tanx-tany)

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  15. Prove that (tan(pi/4+x))/(tan(pi/4-x))=((1+t a n x)/(1-t a n x))^2

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  16. if tanalpha=1/(sqrt(x(x^2+x+1))), tanbeta=(sqrtx)/(sqrt(x^2+x+1) and ...

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  17. Prove that :(tan(A+B))/("cot"(A-B))=(sin^2A-sin^2B)/(cos^2A-sin^2B)

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  18. Prove that : sin^2 6x-sin^2 4x=sin 2x\ sin\ 10 x

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  19. Prove that: cos^2 2x-cos^2 6x= sin4x sin8x

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  20. Prove that: (cos^2 33^@-cos^2 57^@)/(sin^2(21/2)^@-sin^2(69/2)^@)=-sqr...

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