Prove that: `|sintheta."sin"(60-theta).sin(60+theta)|lt=1/4` for all values of `theta` .

Explanation

To prove that \( |\sin \theta \cdot \sin(60^\circ - \theta) \cdot \sin(60^\circ + \theta)| \leq \frac{1}{4} \) for all values of \( \theta \), we can follow these steps:

### Step 1: Rewrite the expression
We start with the expression:
\[ |\sin \theta \cdot \sin(60^\circ - \theta) \cdot \sin(60^\circ + \theta)| \]

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