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If the line (x/a)+(y/b)=1 moves in such ...

If the line `(x/a)+(y/b)=1` moves in such a way that `(1/(a^2))+(1/(b^2))=(1/(c^2))` , where `c` is a constant, prove that the foot of the perpendicular from the origin on the straight line describes the circle `x^2+y^2=c^2dot`

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RD SHARMA ENGLISH-THE STRAIGHT LINES -All Questions
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