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A line through A(-5,-4) meets the lines ...

A line through `A(-5,-4)` meets the lines `x+3y+2=0,2x+y+4=0 and x-y-5=0` at the points `B , Ca n dD` rspectively, if `((15)/(A B))^2+((10)/(A C))^2=(6/(A D))^2` find the equation of the line.

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To find the equation of the line passing through the point \( A(-5, -4) \) that meets the lines \( x + 3y + 2 = 0 \), \( 2x + y + 4 = 0 \), and \( x - y - 5 = 0 \) at points \( B \), \( C \), and \( D \) respectively, we can follow these steps: ### Step 1: Define the Line through Point A Let the slope of the line through point \( A \) be \( m \). The equation of the line in point-slope form is: \[ y + 4 = m(x + 5) \] This can be rearranged to: ...
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