For a frequency distribution mean deviation from mean in computed by: (a) `MdotDdot`=`(sumf)/(sumf|d|)` (b) `MdotDdot=(sumd)/(sumf)` (c) `MdotDdot=(sumfd)/(sumf)` (d) `MdotDdot=(sumf|d|)/(sumf)`

For a frequency distribution standard deviation is computed by applying the formula (a) sigma=sqrt((sumfd^2)/(sumf)-((sumfd)/(sumf))^2) (b) sigma=sqrt(((sumfd^2)/(sumf))-(sumfd^2)/(sumf)) (c) sigma=sqrt((sumfd^2)/(sumf)-(sumfd)/(sumf)) (d) sqrt(((sumfd)/(sumf))^2-(sumfd^2)/(sumf))

For a frequency distribution standard deviation is computed by applying the formula (a) sigma=sqrt((sumfd^2)/(sumf)-((sumfd)/(sumf))^2) (b) sigma=sqrt(((sumfd)/(sumf))^2-(sumfd^2)/(sumf)) (c) sigma=sqrt((sumfd^2)/(sumf)-(sumfd)/(sumf)) (d) sigma=sqrt(((sumfd)/(sumf))^2-(sumfd^2)/(sumf))

The mean deviation of the numbers 3, 4, 5, 6, 7 from the mean is (a) 25 (b) 5 (c) 1.2 (d) 0

For a frequency distribution, mean, median and mode are connected by the relation (a) Mode = 3 Mean – 2 median (b) Mode = 2 Median – 3 Mean (c) Mode = 3 Median – 2 Mean (d) Mode = 3 Median + 2 Mean

The mean of a discrete frequency distribution x_i//f_i ; i=1,\ 2,\ ddot,\ n is given by (a) (sumf_i x_i)/(sumf_i) (b) 1/n\ sum_(i=1)^nf_i x_i (c) (sumi=1nf_i x_i)/(sumi=1n x_i) (d) (sumi=1nf_i x_i)/(sumi=1n i)

Find the mean deviation from the mean of the A.P., a,a+d, a+2d, .........,a+2nd.

If in a frequency distribution, the mean and median are 21 and 22 respectively, then its mode is approximately. (a) 20.5 (b) 22.0 (c) 24.0 (d) 25.5

If the mean of a frequency distribution is 8.1 and sumf_i x_i=132+5k ,\ \ sumf_i=20 , then k= (a) 3 (b) 4 (c) 5 (d) 6

The mean deviation of the numbers 3,4,5,6,7 from the mean is(a) 25 (b) 5 (c) 1.2 (d) 0

The mode of a frequency distribution can be determined graphically from (a) Histogram (b) Frequency polygon (c) Ogive (d) Frequency curve