If the continued product of three numbers in G.P. is 216 and the sum of their products in pairs is 156, find the numbers.

Explanation

Let the numbers are `a/r,a and ar.`

Then, `a/r*a*ar = 216`

`=>a^3 = 216 => a= 6`

Also,

`a/r(a)+a(ar)+a/r(ar) = 156`

`=> a^2(1/r+r+1) = 156`

`=> (1+r+r^2)/r = 156/a^2`

`=> (1+r+r^2)/r = 156/36`

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