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m men and n women ae to be seated in a r...

`m` men and `n` women ae to be seated in a row so that no two women sit together. If `m > n` then show that the number of ways n which they fan be seated as `(m !(m+1)!)/((m-n+1)!)` .

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There are total n women
there are n+1 places for women
`.^nP_r=(n!)/((n-r)!)`
`.^nP_n*.^(n+1)P_n=(n!)/((m-n)!)*((n+1)!)/((m+1-n)!)`
Total possible ways`=((m!)*(m+1)!)/((m-n+1)!)`
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m men and n women are to be seated in a row so that no two women sit together. If (m>n) then show that the number of ways in which they can be seated as (m!(m+1)!)/((m-n+1)!) .

m women and n men are too be seated in a row so that no two men sit together. If mgtn then show that the number of wys in which they can be seated is (m!(m+1)!)/((m-n+1)!)

m women and n men are too be seated in a row so that no two men sit together. If mgtn then show that the number of wys in which they can be seated is (m!(m+1)!)/((m-n+1)!)

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Number iof ways in which m men and n women can be arranged in a rwo so that no two women are together is m!^(m=1)P_n Also number oif ways in which m men and n women can be seated in a row so that all the n women are together is (m=1)!n! On the basis of above informatiion answer the following question: Therre are 10 intermediate stations between two places P and Q. the number of ways in 10 boys &5 girls can be seated in a row so that no boy sits between girls

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