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In how many ways can 5 children the arra...

In how many ways can 5 children the arranged in a row such that two of them, Ram and Shyam, are always together? two of them, Ram and Shyam, are never together?

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To solve the problem of arranging 5 children in a row such that Ram and Shyam are either always together or never together, we can break it down into two parts. ### Part 1: Ram and Shyam are always together 1. **Consider Ram and Shyam as a single unit**: Since Ram and Shyam must be together, we can treat them as one single entity or unit. This means instead of arranging 5 individual children, we are now arranging 4 units: (Ram & Shyam), Child 3, Child 4, and Child 5. 2. **Calculate the arrangements of the units**: The number of ways to arrange these 4 units is given by \(4!\) (4 factorial). \[ ...
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RD SHARMA ENGLISH-PERMUTATIONS-All Questions
  1. How many words can be formed with the letters of the words ‘ORDINATE’ ...

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  2. A code word is to consist of two distinct English alphabets followed b...

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  3. In how many ways can 5 children the arranged in a row such that two of...

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  4. How many words can be formed from the letters of the word, TRIANGLE? ...

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  5. (i) How many different words can be formed with letters of the word ‘S...

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  6. In how many ways can 5 girls and 3 boys be seated in a row so that ...

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  7. How many words can be formed with the letters of the words ‘ORDINATE’ ...

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  8. When a group photograph is taken, all the seven teachers should be in ...

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  9. In a class of 10 students there are 3 girls A, B, C. In how many di...

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  10. Compute: (20 !)/(18 !)

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  11. Compute: (10 !)/(6! 10 !)

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  12. Convert the following products into factorial: 6.7.8.9.10

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  13. Convert the following products into factorial: 2.4.6.8.10

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  14. Find the LCM of 4! 5! and 6!

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  15. Compute: (30 !)/(28 !)

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  16. Compute: (11 !-10 !)/(9!)

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  17. Prove that: 1/(9!)+1/(10 !)+1/(11 !)=(122)/(11 !)

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  18. Find\ x in each of the following: 1/(4!)+1/(5!)=x/(6!)

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  19. Find\ x in each of the following: x/(10 !)=1/(8!)+1/(9!)

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  20. Find\ x in each of the following: 1/(6!)+1/(7!)=x/(8!)

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