Home
Class 11
MATHS
If the equation of a circle is lambdax^2...

If the equation of a circle is `lambdax^2+(2lambda-3)y^2-4x+6y-1=0,` then the coordinates of centre are

Text Solution

AI Generated Solution

To find the coordinates of the center of the circle given by the equation: \[ \lambda x^2 + (2\lambda - 3)y^2 - 4x + 6y - 1 = 0, \] we will follow these steps: ...
Doubtnut Promotions Banner Mobile Dark
|

Topper's Solved these Questions

  • STATISTICS

    RD SHARMA ENGLISH|Exercise All Questions|216 Videos

  • THE STRAIGHT LINES

    RD SHARMA ENGLISH|Exercise All Questions|493 Videos

Similar Questions

Explore conceptually related problems

If (4, 1) be an end of a diameter of the circle x^2 + y^2 - 2x + 6y-15=0 , find the coordinates of the other end of the diameter.

Find the parametric equation of the circles : 3x^2 + 3y^2 + 4x-6y - 4 = 0

Knowledge Check

  • If one end of a diameter of the circle x^(2) + y^(2) - 4x - 6y + 11 = 0 is (3, 4), then the coordinates of the other end of the diameter are

    A
    (a) (2,1)
    B
    (b) (-2,1)
    C
    (c) (1,2)
    D
    (d) (-1,-2)

  • If the equation (4 lambda - 3) x^(2) + lambda y ^(2) + 6x - 2y + 2 = 0 represents a circle, then its centre is

    A
    (a) (3,-1)
    B
    (b) (3,1)
    C
    (c) (-3,1)
    D
    (d) (-3,-1)

    • Similar Questions

    Explore conceptually related problems

    Find the centre and radius of the the circles: x^2 +y^2 - 4x-6y-14=0

    Find the equation of the circle which is concentric with the circle x^2 +y^2 - 4x+6y-3=0 and the double of its area.

    Find the equation of the tangent to the circle x^2 + y^2-30x+6y+109=0 at (4, -1)

    If the equation 3x^2 + 3y^2 + 6lambdax + 2lambda = 0 represents a circle, then the value of lambda . lies in

    The equation of the chord of the circle x^(2)+y^(2)-4x+6y-3=0 having (1,-2) as it midpoint is

    The equation of the normal to the circle x^(2)+y^(2)+6x+4y-3=0 at (1,-2) to is

    Home
    Profile