If `x_n`=cos`pi/(2^n)`+isin`pi/(2^n)` , prove that `x_1x_2x_3 x_oo=-1.`

Explanation

To prove that \( x_1 x_2 x_3 \ldots x_\infty = -1 \), we start with the given expression for \( x_n \):

\[ x_n = \cos\left(\frac{\pi}{2^n}\right) + i \sin\left(\frac{\pi}{2^n}\right) \]

Using Euler's formula, we can express this as:

...