Prove that there is no term involving `x^6` in the expansion of `(2x^2-3/x)^(11)` , where `!=0.`

Explanation

To prove that there is no term involving \( x^6 \) in the expansion of \( (2x^2 - \frac{3}{x})^{11} \), we can follow these steps:

### Step 1: Identify the general term in the binomial expansion
The general term (the \( (r+1) \)-th term) in the expansion of \( (a + b)^n \) is given by:
\[ T_{r+1} = \binom{n}{r} a^{n-r} b^r \]
For our expression, \( a = 2x^2 \), \( b = -\frac{3}{x} \), and \( n = 11 \).
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