`cos(sin^-1 (3/5)+ cot^-1(3/2)) = 6/(5sqrt13)`

Explanation

To prove that \( \cos(\sin^{-1}(3/5) + \cot^{-1}(3/2)) = \frac{6}{5\sqrt{13}} \), we will follow these steps:

### Step 1: Define the angles
Let:
\[ \theta = \sin^{-1}\left(\frac{3}{5}\right) \]
\[
...