Find the remainder when `f(x)=x^3-6x^2+2x-4` is divided by `g(x)=3x-1.`

Explanation

When f(x) is divided by then remainder =f(a)

`g(x)=3x-1=3(x-1/3)`

`a=1/3`

Rem`=f(1/3)=(1/3)^3-6(1/3)^2+2(1/3)-4`

`=1/27-6/9+2/3-4`

`=1/27-4`

`=-107/27`.