In an isosceles triangle altitude from the vertex bisects the base. GIVEN : An isosceles triangle `A B C` such that `A B=A C` and an altitude `A D` from `A` on side `B Cdot` TO PROVE : `D` bisects `B C` i.e. `B D=D Cdot` Figure

Explanation

To solve the problem, we will follow a structured approach to prove that in an isosceles triangle, the altitude from the vertex bisects the base.

### Step-by-Step Solution:

1. **Given Information**:
- We have an isosceles triangle \( ABC \) where \( AB = AC \).
- An altitude \( AD \) is drawn from vertex \( A \) to side \( BC \).

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