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A D and B C are equal perpendiculars to ...

`A D` and `B C` are equal perpendiculars to a line segment `A B` . Show that `C D` bisects `A Bdot`

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To prove that line segment \( CD \) bisects line segment \( AB \), we will follow these steps: ### Step-by-Step Solution: 1. **Identify the Given Information:** We are given that \( AD \) and \( BC \) are equal perpendiculars to the line segment \( AB \). This means: - \( AD = BC \) - \( AD \perp AB \) ...
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RD SHARMA ENGLISH-CONGRUENT TRIANGLE -All Questions
  1. If A B C is an isosceles triangle with A B=A C . Prove that the ...

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  2. If the altitudes from two vertices of a triangle to the opposite si...

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  3. A D and B C are equal perpendiculars to a line segment A B . Show that...

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  4. In A B C ,A B=A C , and the bisectors of angles B and C intersec...

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  5. In Figure, it is given that A B=E F ,B C=D E ,A B|B D and F E|C Edot P...

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  6. In Figure, it is given that A B=B C and A D=E C . Prove that A B E~=C ...

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  7. In Figure, l II m and M is the mid-point of the line segment A Bdot P...

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  8. In Figure, line l is the bisector of angle A and B is any point on l ....

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  9. In Figure, O is the mid point of A B and C D . Prove that (i) A O C~...

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  10. Prove that measure of each angle of an equilateral triangle is 60^0...

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  11. In Figure, it is given that A E=A D and B D=C Edot Prove that triangl...

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  12. In Figure, it is given that A B=C F ,E F=B D and /A F E=/C B Ddot Prov...

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  13. Two triangles are congruent if two sides and the included angle of ...

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  14. In DeltaABC ,/A=100^0 and A B=A Cdot Find /B and /C

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  15. Angles opposite to two equal sides of a triangle are equal. GIVEN :...

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  16. In Figure, X and Y are two points on equal sides A B and A C of a A B ...

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  17. Prove that the angle between internal bisector of one base angle an...

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  18. In A B C and P Q R Figure, A B=P Q ,B C=Q R and C B and R Q are extend...

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  19. In Figure, the side B C of A B C is produced to form ray B D as shown....

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  20. In a triangle the greater angle has the longer side opposite to it.

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