In Figure, the side `B C` of `A B C` is produced to form ray `B D` as shown. Ray `C E` is drawn parallel to `B A` . Show directly, without using the angle sum property of a triangle that `/_A C D=/_A+/_B` and deduced that `/_A+/_B+/_C=180^0dot`

Explanation

To solve the problem, we need to demonstrate that \( \angle ACD = \angle A + \angle B \) and then deduce that \( \angle A + \angle B + \angle C = 180^\circ \).

### Step-by-Step Solution:

1. **Identify the Given Information**:
- We have triangle \( ABC \) where side \( BC \) is extended to form ray \( BD \).
- Ray \( CE \) is drawn parallel to \( AB \).

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