If `A B C` is an isosceles triangle such that `A B=A C` and `A D` is an altitude from `A` on `B C` . Prove that (i) `/_B=/_C` (ii) `A D` bisects `B C` (iii) `A D` bisects `/_A`

Explanation

To solve the problem step by step, we will prove the three statements regarding the isosceles triangle \( ABC \) with \( AB = AC \) and the altitude \( AD \) from \( A \) to \( BC \).

### Step 1: Draw the Triangle
Draw triangle \( ABC \) with \( AB = AC \). Mark point \( D \) on line \( BC \) such that \( AD \) is perpendicular to \( BC \).

### Step 2: Identify the Right Angles
Since \( AD \) is an altitude, we have:
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