If PS is the bisector of `/_Q P R` and `P T_|_Q R` . Show that `/_T P S=1/2(/_Q-/_R)dot`

Explanation

To solve the problem, we need to show that if PS is the bisector of angle QPR and PT is perpendicular to QR, then angle TPS = 1/2 (angle Q - angle R).

### Step-by-Step Solution:

1. **Draw Triangle PQR**:
- Start by sketching triangle PQR where P is the vertex, and Q and R are the other two vertices.

**Hint**: Remember that P is the vertex where the angle is being bisected.
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