In a triangle `A B C ,/_A B C=/_A C B` and the bisectors of `/_A B C` and `/_A C B` intersect at `O` such that `/_B O C=120^0dot` Show that `/_A=/_B=/_C=60^0`

Explanation

To solve the problem, we need to show that in triangle ABC, where ∠ABC = ∠ACB and the angle bisectors of these angles intersect at point O such that ∠BOC = 120°, the angles A, B, and C are all equal to 60°.

### Step-by-Step Solution:

1. **Identify the Given Information**:
- Triangle ABC with ∠ABC = ∠ACB.
- The bisectors of ∠ABC and ∠ACB intersect at point O.
- ∠BOC = 120°.
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