Prove that A diagonal of a parallelogram divides it into two triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area.

Show that the diagonals of a parallelogram divide it into four triangles of equal area. GIVEN : A parallelogram A B C D . The diagonals A C and B D intersect at Odot TO PROVE : a r( O A B)=a r( O B C)=a r( O C D)=a r( A O D)

A diagonal of parallelogram divides it into two congruent triangles.

Show that a median of a triangle divides it into two triangles of equal areas.

Show that a median of a triangle divides it into two triangles of equal area.

The diagonal AC of a quadrilateral ABCD divides it into two triangles of equal areas. Prove that diagonal AC bisects the diagonal BD.

Show that : (i) a diagonal divides a parallelogram into two triangles of equal area. (ii) the ratio of the areas of two triangles of the same height is equal to the ratio of their bases. (iii) the ratio of the areas of two triangles on the same base is equal to the ratio of their heights.

Show that a median of a triangle divides it into two triangles of equal area. GIVEN : A triangle A B C in which A D is the median. TO PROVE : a r(triangle A B D)=a r( triangle A D C) CONSTRUCTION : Draw A L_|_B C

Prove that the diagonals of a parallelogram bisect each other.