If the bisectors of the opposite angles `/_Aa n d/_B` of a cyclic quadrilateral `A B C D` intersect the corresponding cicle at `P an d Q` respectively, then `P Q` is a diameter of the circle.

Explanation

To solve the problem, we need to prove that the line segment \( PQ \) is a diameter of the circle, given that \( P \) and \( Q \) are the points where the angle bisectors of angles \( A \) and \( B \) of a cyclic quadrilateral \( ABCD \) intersect the circle.

### Step-by-Step Solution:

1. **Identify the Given Information:**
- We have a cyclic quadrilateral \( ABCD \).
- The angle bisector of angle \( A \) intersects the circle at point \( P \).
- The angle bisector of angle \( B \) intersects the circle at point \( Q \).
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