If twice the son’s age in years is added to the father’s age, the sum is 70. But if twice  the father’s age is added to the son’s age, the sum is 95. Find the ages of father and son.

If twice the sons age in years is added to the fathers age, the sum is 70. But if twice the others age is added to the sons age, the sum is 95. Find the ages of father and son.

A son's age is 27 years less than his father's age. Write the son's age in terms of the father's age.

A boy is 30 years younger than this father. If the sum of the ages of the son and the father is 56, find the age of the son.

A father is three times as old as his son. In 12 years time, he will be twice as old as his son. Find the present ages of father and the son.

Two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of father and son.

The age of the father is twice the sum of the ages of his two children. After 20 yr, his age will be equal to the sum of the ages of his children. Find the age of the father.

The sum of ages of father and his son is 75 years. If the age of the son is 25 years, find the age of the father.

Father’s age is three times the sum of ages of his two children. After 5 years his age will be twice the sum of ages of two children. Find the age of father.

The sum of the ages of a man and his son is 45 years. Five years ago, the product of their ages was four times the man’s age at the time. Find their present ages.

Mrs. Mehra has two sons, one being exactly one year older than the other. At present, her age is equal to the sum of squares of ages of her sons. If 4 years hence her age becomes five times the age of the elder son then find the present ages of her sons.