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In A B C , the bisector of /B meets A C...

In ` A B C` , the bisector of `/_B` meets `A C` at `D`. A line `PQ||AC` meets `A B , BC and BD` at `P ,Q and R` respectively. Show that (i) `PR*BQ=QR*BP` (ii) `AB*CQ=BC*AP`

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