A ladder rests against a wall at an angle `alpha` to the horizontal. Its foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making an angle `beta` with the horizontal. Show that: `a=b tan(1/2(α+β))`.

A ladder rests against a vertical wall at angle alpha to the horizontal . If is foot is pulled away from the wall through a distance 'a' so that it slides a distance 'b' down the wall making the angle beta with the horizontal , then a =

A ladder rest against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance x , so that it slides a distance y down the wall making an angle beta with the horizontal. THEN x=

A ladder rest against a wall making an angle alpha with the horizontal. The foot of the ladder is pulled away from the wall through a distance x , so that it slides a distance y down the wall making an angle beta with the horizontal. Prove that x=ytan(alpha+beta)/2dot

A ladder rests against a vertical wall at an angle alpha to the horizontal. If the foot is pulled away through a distance 2m, then it slides a distance 5 m down the wall, finally making an angle beta with the horizontal. The value of tan((alpha+beta)/(2)) is equal to

A ladder rests against a vertical wall at inclination alpha to the horizontal. Its foot is pulled away from the wall through a distance p so that it's upper end slides q down the wall and then ladder make an angle beta to the horizontal show that p/q = ( cos beta - cos alpha)/(sin alpha - sin beta) .

A ladder rests against a vertical wall at inclination alpha to the horizontal. Its foot is pulled away from the wall through a distance p so that it's upper end slides q down the wall and then ladder make an angle beta to the horizontal show that p/q = ( cos beta - cos alpha)/(sin alpha - sin beta) .

A ladder leaning against a wall makes an angle of 60° with the horizontal. If the foot of the ladder is 2.5 m away from the wall, find the length of the ladder.

A ball is projected at t = 0 with velocity v_0 at angle theta with horizontal. It strikes a smooth wall at a distance from it and then falls at a distance d from the wall. Coefficient of restitution is 'e' then :

A ladder 3.7 m long is placed against a wall in such a way that the foot of the ladder is 1.2 m away from the wall. Find the height of the wall to which the ladder reaches.

A 13 m long ladder is leaning against a wall, touching the wall at a certain height from the ground level. The bottom of the ladder is pulled away from the wall, along the ground, at the rate of 2 m/s. How fast is the height on the wall decreasing when the foot of the ladder is 5 m away from the wall ?