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The elevation of a tower at a station A due north of it is `alpha` and at a station B due west of A is `beta`. Prove that the height of the tower is `(ABsinalphasinbeta)/(sqrt(sin^2alpha -sin^2beta))`

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The elevation of a tower at a station A due North of it is alpha and at a station B due West of A is beta . Prove that height of the tower is (A B sinalpha sinbeta)/(sin^2alpha-sin^2beta) .

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Prove that: tan(alpha+beta)tan(alpha-beta)=(sin^2 alpha-sin^2 beta)/(cos^2 alpha-sin^2 beta)

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RD SHARMA ENGLISH-SOME APPLICATIONS OF TRIGONOMETRY-All Questions
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