If the standard deviation of a variable `X \ is \ sigma` , then standard deviation of variable `(a X+b)/c` is (a) `asigma` (b) `a/csigma` (c) `|a/c|sigma` (d) `(asigma+b)/c`

If standard deviation of 1,2,3,4,….,10 is sigma then standard deviation of 11, 12, …20 is

If standard deviation of 1,2,3,4….,10 is sigma then, show that standard deviation of 11, 12,…. , 20 is sigma

Let x_(1),x_(2),x_(3),……..,x_(n) be n observations with mean barx and standard deviation sigma . The mean the standard deviation of kx_(1),kx_(2),……,kx_(n) respectively are (i) barx,ksigma (ii) kbarx,sigma (iii) kbarx,ksigma (iv) barx,sigma

For the following probability distribution determine standard deviation of the random variable X.

The standard deviation of first 10 natural numbers is a) 8.25 (b) 6.5 (c) 3.87 (d) 2.87

The standard deviation of first 10 natural numbers is (a) 8.25 (b) 6.5 (c) 3.87 (d) 2.87

The standard deviation of first 10 natural numbers is (a) 8.25 (b) 6.5 (c) 3.87 (d) 2.87

Let a, b, c, d, e, be the observations with mean m and standard deviation s. The standard deviation of the observations a+k, b+k, c+k, d+k, e+k is (a) s (b) k s (c) s+k (d) s/k

Given r= sqrt((3)/(4)), b_(yx)= (1)/(2) , variance of x=12, then standard deviation of y is

Let x_1, x_2, ,x_n be x_n observations. Let y_i=a x_i+b for i=1,2,...,n where a and b are constants. If the mean of x_i's is 48 and their standard deviation is 12, the mean of y_i 's is 55 and standard deviation of y_i's is 15, the values of a and b are (a) a=1. 25 ,b=-5 (b) a=-1. 25 ,b=5 (c) a=2. 5 ,b=-5 (d) a=2. 5 ,b=5