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Let `x_1, x_2, ... ,x_n` be n observations and `barX ` be their arithmetic mean. The standard deviation is given by (a) `sum_(i=1)^n(x_i- barX )^2` (b) `1/nsum_(i=1)^n(x_i- barX )^2` (c) `sqrt(1/nsum_(i=1)^n(x_i- X )^2)` (c) `1/nsum_(i=1)^n x_i^2- barX ^2`

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