Solve the following equation for `x`: `tan^(-1)((2x)/(1-x^2))+cot^(-1)((1-x^2)/(2x))=(2pi)/3,x >0`

Explanation

To solve the equation

\[ \tan^{-1}\left(\frac{2x}{1-x^2}\right) + \cot^{-1}\left(\frac{1-x^2}{2x}\right) = \frac{2\pi}{3}, \quad x > 0, \]

we can follow these steps:

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