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If (x+y)^3-\ (x-y)^3-6y\ (x^2-y^2)=\ k y...

If `(x+y)^3-\ (x-y)^3-6y\ (x^2-y^2)=\ k y^3,` then `k=`
(a)1
(b) 2
(c) 4
(d) 8

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