If `sintheta+costheta=sqrt(2)sin(90^@-theta)` , determine `cottheta` .

If sintheta+costheta=sqrt(2)cos(90o-theta) , find cottheta .

Let P = [theta : sintheta – costheta = sqrt2 costheta) andQ= {theta : sintheta + costheta = 12 sintheta} be two sets. Then:

If costheta-sintheta=sqrt(2)sintheta , then prove that: costheta+sintheta=sqrt(2)costheta

If costheta+sintheta=sqrt(2)costheta ,then find the value of (costheta-sintheta)/(sintheta) .

If sin theta-sqrt(6)costheta=sqrt(7)costheta. Prove that cos theta+sqrt6 sin theta-sqrt7 sin theta=0.

Prove that : (i) sinthetacos(90^(@)-theta)+sin(90^(@)-theta)costheta=1 (ii) sectheta" cosec"(90^(@)-theta)-tanthetacot(90^(@)-theta)=1 (iii) (sintheta*sec(90^(@)-theta)cot(90^(@)-theta))/("cosec"(90^(@)-theta)*costheta*tantheta)-(tan(90^(@)-theta))/(cottheta)=0 (iv) (1+sin(90^(@)-theta))/(cos(90^(@)-0))+(cos(90^(@)-theta))/(1+sin(90^(@)-0))=2"cosec"theta

(sintheta)/(1+costheta) + (1+costheta)/(sintheta) = 2 cosec theta

If int(sintheta-costheta)/((sintheta+costheta)sqrt(sinthetacostheta+sin^(2)thetacos^(2)theta))d theta = "cosec"^(_1)(f(theta))+C , then

Let P={theta:sintheta-costheta=sqrt2costheta}and Q={theta: sintheta+costheta=sqrt2sintheta} be two sets. Then

Prove that : (sinthetacos(90^0-theta)costheta)/(sin(90^0-theta))+(costhetasin(90^0-theta)sintheta)/(cos(90^0-theta))=1