`(sintheta)/(1+costheta)` is equal to
(a)`(1+costheta)/(sintheta)`
(b) `(1-costheta)/(costheta)`
(c) `(1-costheta)/(sintheta)`
(d) `(1-sintheta)/(costheta)`

Prove: (costheta)/(1+sintheta)=(1-sintheta)/(costheta)

Prove: (1-costheta)/(sintheta)=(sintheta)/(1+costheta)

Prove: (costheta)/(1-sintheta)=(1+sintheta)/(costheta)

(1+costheta+sintheta)/(1+costheta-sintheta)=(1+sintheta)/(costheta)

(sintheta)/(1+costheta) + (1+costheta)/(sintheta) = 2 cosec theta

If sintheta=a/b , then costheta is equal to

If alpha, beta are roots of x^2 sintheta-(costhetasintheta+1)x+costheta=0 where alphaltbeta and thetaepsilon(0,pi//4) then value of sum_(n=0)^oo(alpha^n +((-1)^n)/beta^n) (A) (1-costheta)/(sintheta)+(1-sintheta)/(costheta) (B) 1/(1+costheta)+1/(1-sintheta) (C) 1/(1-costheta)+1/(1-sintheta) (D) 1/(1-costheta) +1/(1+sintheta)

Prove that (1-sintheta+costheta)^2=2(1+costheta)(1-sintheta)

Prove that : (1-costheta)/(sintheta)+(sintheta)/(1-costheta)=2"cosec "theta

If I=[(1 ,0),( 0, 1)] , J=[(0, 1),(-1 ,0)] and B=[(costheta,sintheta),(-sintheta,costheta)] , then B equals a) Icostheta+Jsintheta (b) Isintheta+Jcostheta (c) Icostheta-Jsintheta (d) Icostheta+Jsintheta