The first three terms of an A.P. respectively are `3y-1,\ 3y+5` and `5y+1` . Then, `y`
equals
(a) `-3` (b) `4` (c) `5` (d) `2`

If a, b, c are three consecutive terms of an A.P. and x,y,z are three consecutive terms of a G.P., then prove that x^(b-c) . y^(c-a).z^(a-b)=1

If xdy=ydx+y^2dy and y(1)=1 , then y(-3) is equal to (A) 1 (B) 5 (C) 4 (D) 3

If (x + 1), 3x and (4x + 2) are first three terms of an A.P. then its 5^(th) term is

If the maximum and minimum values of y=(x^2-3x+c)/(x^2+3x+c) are 7 and 1/7 respectively then the value of c is equal to (A) 3 (B) 4 (C) 5 (D) 6

The coefficient of x^2 in -5/3\ x^2y is equal to :- (a) -5/3 (b) -5/3y (c) 5/3 (d) 5/3y

If the mean of the following distribution is 2.6, then the value of y is Variable (x) : 1 2 3 4 5 Frequency (y) : 4 5 y 1 2 (a) 3 (b) 8 (c) 13 (d) 24

For the primitive integral equation y dx+y^2dy=xdy ; x in R ,y >0,y(1)=1, then y(-3) is (a) 3 (b) 2 (c) 1 (d) 5

The equation of the transvers and conjugate axes of a hyperbola are, respectively, x+2y-3=0 and 2x-y+4=0 , and their respective lengths are sqrt(2) and 2/sqrt(3)dot The equation of the hyperbola is a) 2/5(x+2y-3)^2-3/5(2x-y+4)^2=1 b) 2/5(x-y-4)^2-3/5(x+2y-3)^2=1 c) 2/5(2x-y+4)^2-3/5(x+2y-3)^2=1 d) 2(x+2y-3)^2-3(2x-y+4)^2=1

If the point P(x ,\ y) is equidistant from A(5,\ 1) and B(-1,\ 5) , then (a) 5x=y (b) x=5y (c) 3x=2y (d) 2x=3y

Let A,B, and C be three sets such that A={(x,y)|(x)/(cos theta)=(y)/(sintheta)=5,"where" 'theta'"is parameter"} B= {(x,y)|(x-3)/(cos phi)=(y-4)/(sin phi)=r} C= { (x,y)|(x-3)^(2)+(y-4)^(2)leR^(2)} If phi is fixed and r varies and (A cap B) =1 , then sec phi is equal to (a) (5)/(4) (b) (-5)/(4) (c) (5)/(3) (d) (-5)/(3)