Two persons are 'a' metres apart and the height of one is double that of the other. If from the middle point of the line joining their feet, an observer finds the angular elevation of their tops to be complementary, then the height of the shorter post is (a)`a/4` (b) `a/(sqrt(2))` (c) `asqrt(2)` (d) `a/(2sqrt(2))`

Two poles are a metres apart and the height of one is double of the other. If from the middle point of the line joining their feet an observer finds the angular elevations of their tops to be complementary, then the height of the smaller is (a) sqrt(2)am e t r e s (b) a/(2sqrt(2))m e t r e s (c) a/(sqrt(2))m e t r e s (d) 2am e t r e s

If the angles of elevation of a tower from two points distant a and b from the base and in the same straight line with it are complementary, then the height of the tower is (a) a b (b) sqrt(a b) (c) a/b (d) sqrt(a/b)

If the angles of elevation of the top of a tower from two points at a distance of 4m and 9m from the base of the tower and in the same straight line with it are complementary, find the height of the tower.

The angle of elevation of the top of a tower from two distinct points s and t from foot are complementary. Prove that the height of the tower is sqrt[st] .

The angles of elevation of the top of a tower from two points at a distance of 4 m and 9 m from the base of the tower and in the same straight line with it are complementary. Prove that the height of the tower is 6m.

If the angle of elevation of a tower from a distance of 100 metres from its foot is 60^@ , then the height of the tower is (a) 100sqrt(3)m (b) (100)/(sqrt(3))m (c) 50sqrt(3)m (d) (200)/(sqrt(3))m

A tower stands at the centre of a circular park. A and B are two points on the boundary of the park such that A B""(=""a) subtends an angle of 60^@ at the foot of the tower, and the angle of elevation of the top of the tower from A or B is 30^@ . The height of the tower is (1) (2a)/(sqrt(3)) (2) 2asqrt(3) (3) a/(sqrt(3)) (4) asqrt(3)

Two poles of height a metres and b metres are p metres apart. Prove that the height of the point of intersection of the lines joining the top of each pole to the foot of the opposite pole is given by (a b)/(a+b) metres.

The angle of elevation of the top of a tower at a point on the ground 50m away from the foot of the tower is 45^0dot Then the height of the tower (in metres) is 50sqrt(3) (b) 50 (c) (50)/(sqrt(2)) (d) (50)/(sqrt(3))

On a straight line passing through the foot of a tower, two points C and D are at distances of 4 m and 16 m from the foot respectively. If the angles of elevation from C and D of the top of the tower are complementary, then find the height of the tower.