It is found that on walking `x` metres towards a chimney in a horizontal line through its base, the elevation of its top changes from `30o` to `60o` . The height of the chimney is `3sqrt(2)x` (b) `2sqrt(3)x` (c) `(sqrt(3))/2x` (d) `2/(sqrt(3))x`

Find the height of a tree it is found that on walking away from is 20 m, in a horizontal line through is base , the elevation of its top changes from 60^(@) t o 30^(@)

Find the height of a building, when it is found that on walking towards it 40 m in a horizontal line through its base the angular elevation of its top changes from 30^(@) t o 45^(@)

The graph of straight line y = sqrt(3)x + 2sqrt(3) is :

Solve sqrt(2x+1)+sqrt(3x+2)=sqrt(5x+3)

The length of the shadow of a tower standing on level ground is found to be 2x metres longer when the suns elevation is 30o than when it was 45o . The height of the tower in metres is (sqrt(3)+1)x (b) (sqrt(3)-1)x (c) 2sqrt(3)x (d) 3sqrt(2)x

int(x+3sqrt(x^(2))+6sqrt(x))/(x(1+3sqrt(x)))dx

Factorise sqrt(3)x^(2)+10x+3sqrt(3)

Solve sqrt(3x)-sqrt(x)=2 .

A man observes the angle of elevation of the top of a building to be 30^(@) . He walks towards it in a horizontal line through its base. On covering 60 m the angle of elevation changes to 60^(@) . Find the height of the building correct to the nearest metre.

AB is a vertical pole with B at the ground level and A at the top. A man finds that the angle of elevation of the point A from a certain point C on the ground is 60o . He moves away from the pole along the line BC to a point D such that C D""=""7""m . From D the angle of elevation of the point A is 45o . Then the height of the pole is (1) (7sqrt(3))/2 1/(sqrt(3)-1)m (2) (7sqrt(3))/2 sqrt(3)+1m (3) (7sqrt(3))/2 sqrt(3)-1m (4) (7sqrt(3))/2 sqrt(3)+1m