The perimeter of the triangle formed by the points `(0,\ 0),\ (1,\ 0)` and `(0,\ 1)` is `1+-sqrt(2)` (b) `sqrt(2)+1` (c) `3` (d) `2+sqrt(2)`

The centroid of the triangle with vertices (1, sqrt(3)), (0, 0) and (2, 0) is

The incenter of the triangle with vertices (1,sqrt(3)),(0,0), and (2,0) is (a) (1,(sqrt(3))/2) (b) (2/3,1/(sqrt(3))) (c) (2/3,(sqrt(3))/2) (d) (1,1/(sqrt(3)))

The orthocentre of the triangle formed by the lines x y=0 and x+y=1 is (a) (1/2,1/2) (b) (1/3,1/3) (c) (0,0) (d) (1/4,1/4)

The distance between the orthocentre and circumcentre of the triangle with vertices (1,2),\ (2,1)\ a n d\ ((3+sqrt(3))/2,(3+sqrt(3))/2) is a. 0 b. sqrt(2) c. 3+sqrt(3) d. none of these

The point on the curve x^2=2y which is nearest to the point (0, 5) is(A) (2sqrt(2),4) (B) (2sqrt(2),0) (C) (0, 0) (D) (2, 2)

If (0,1),(1,1)a n d(1,0) be the middle points of the sides of a triangle, its incentre is (2+sqrt(2),2+sqrt(2) ) (b) [2+sqrt(2),-(2+sqrt(2))] (2-sqrt(2),2-sqrt(2)) (d) [2-sqrt(2),(2+sqrt(2))]

If (0,1),(1,1)a n d(1,0) be the middle points of the sides of a triangle, its incentre is (2+sqrt(2),2+sqrt(2) ) (b) [2+sqrt(2),-(2+sqrt(2))] (2-sqrt(2),2-sqrt(2)) (d) [2-sqrt(2),(2+sqrt(2))]

On the line segment joining (1, 0) and (3, 0) , an equilateral triangle is drawn having its vertex in the fourth quadrant. Then the radical center of the circles described on its sides. (a) (3,-1/(sqrt(3))) (b) (3,-sqrt(3)) (c) (2,-1sqrt(3)) (d) (2,-sqrt(3))

Consider a branch of the hypebola x^2-2y^2-2sqrt2x-4sqrt2y-6=0 with vertex at the point A. Let B be one of the end points of its latus rectum. If C is the focus of the hyperbola nearest to the point A, then the area of the triangle ABC is (A) 1-sqrt(2/3) (B) sqrt(3/2) -1 (C) 1+sqrt(2/3) (D) sqrt(3/2)+1

int_0^(sqrt(2)) [x^2] dx is equal to (A) 2-sqrt(2) (B) 2+sqrt(2) (C) sqrt(2)-1 (D) sqrt(2)-2