`P` is a point on the bisector of an angle `/_A B Cdot` If the line through `P` parallel to `A B` meets `B C` at `Q` , prove that triangle `B P Q` is isosceles.

P is a point on the bisector of angle ABC .If the line through P , parallel to BA meet at Q ,prove that Delta BPQ is an isosceles triangle.

P is the mid-point of side A B of a parallelogram A B C D . A line through B parallel to P D meets D C at Q\ a n d\ A D produced at R . Prove that: (i) A R=2B C (ii) B R=2\ B Q

P is the mid-point of side A B of a parallelogram A B C D . A Line through B parallel to P D meets D C at Q and A D produced at R . Prove that (i) A R=2B C (ii) B R=2B Qdot

The bisectors of the angles B and C of a triangle A B C , meet the opposite sides in D and E respectively. If DE||BC , prove that the triangle is isosceles.

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A parallel to C P meets C B produced in Q and the parallelogram P B Q R completed. Show that a r(llgm A B C D)=a r(llgm B P R Q)dot CONSTRUCTION : Join A C and PQ. TO PROVE : a r(llgm A B C D)=a r(llgm B P R Q)

The side A B of a parallelogram A B C D is produced to any point Pdot A line through A parallel to C P meets C B produced in Q and the parallelogram P B Q R completed. Show that a r(^(gm)A B C D)=a r(^(gm)B P R Q)dot CONSTRUCTION : Join A C and PQ. TO PROVE : a r(^(gm)A B C D)=a r(^(gm)B P R Q)

In triangle ABC, P is the mid-point of side BC. A line through P and parallel to CA meets AB at point Q and a line through Q and a line through Q and parallel to BC meets median AP at point R. Prove that : BC=4QR .

In triangle ABC, P is the mid-point of side BC. A line through P and parallel to CA meets AB at point Q and a line through Q and parallel to BC meets median AP at point R. Prove that : AP=2AR

A B C D is a quadrilateral. A line through D , parallel to A C , meets B C produced in P as shown in figure. Prove that a r (triangle A B P) =a r (Quad. A B C D) .

Two equal circles intersect in P and Q . A straight line through P meets the circles in A and B . Prove that Q A=Q Bdot