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P is the mid-point of side B C of a pa...

`P` is the mid-point of side `B C` of a parallelogram `A B C D` such that `/_B A P=/_D A Pdot` If `A D=10 c m ,\ ` then `C D=`

A

5cm

B

10cm

C

6cm

D

8cm

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To solve the problem step by step, we will follow the reasoning provided in the video transcript. ### Step-by-Step Solution: 1. **Identify the Given Information:** - We have a parallelogram ABCD. - P is the midpoint of side BC. - The angles \( \angle BAP \) and \( \angle DAP \) are equal. - The length of side AD is given as 10 cm. 2. **Understanding the Properties of Parallelogram:** - In a parallelogram, opposite sides are equal and parallel. - Therefore, \( AD \parallel BC \) and \( AB \parallel CD \). 3. **Using the Midpoint:** - Since P is the midpoint of BC, we can say: \[ BP = \frac{1}{2} BC \] - Let's denote \( BC \) as \( x \). Then: \[ BP = \frac{x}{2} \] 4. **Using the Angle Equality:** - Since \( \angle BAP = \angle DAP \), we can conclude that triangle APB is isosceles because it has two angles equal. - Therefore, the sides opposite these angles are equal: \[ AB = AP \] 5. **Relating Sides Using the Isosceles Triangle Property:** - In triangle APB, since \( BP = \frac{x}{2} \) and \( AB = AP \), we can say: \[ AB = BP = \frac{x}{2} \] 6. **Using the Property of Parallelograms:** - In parallelogram ABCD, opposite sides are equal, so: \[ AB = CD \] - Thus, we can write: \[ CD = \frac{x}{2} \] 7. **Relating BC and AD:** - Since \( AD \) is equal to \( BC \) in a parallelogram, we have: \[ AD = x \] - Given that \( AD = 10 \, \text{cm} \), we can substitute: \[ x = 10 \, \text{cm} \] 8. **Finding CD:** - Now substituting \( x \) back into the equation for \( CD \): \[ CD = \frac{x}{2} = \frac{10}{2} = 5 \, \text{cm} \] ### Final Answer: Thus, the length of \( CD \) is \( 5 \, \text{cm} \).
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