Show that the area of a rhombus is half the product of the lengths of its diagonals.

Given that the side length of a rhombus is the geometric mean of the length of its diagonals. The degree measure of the acute angle of the rhombus is (a) 15^0 (b) 30^0 (c) 45^0 (d) 60^0

Given that the side length of a rhombus is the geometric mean of the length of its diagonals. The degree measure of the acute angle of the rhombus is 15^0 (b) 30^0 (c) 45^0 (d) 60^0

Prove that the sum of the squares of the sides of a rhombus is equal to the sum of the squares of its diagonals.

Prove that the sum of the squares of the sides of a rhombus is equal to the sum of the squares of its diagonals.

Prove that the area of a rhombus is equal to half the rectangle contained by its diagonals. Given: A rhombus A B C D such that its diagonals A C\ a n d\ B D intersect at O . To Prove: a r\ (r hom b u s\ A B C D)=1/2 (area of the rectangle contained by its diagonals =1/2(A C\ times\ B D)

The diagonals of as parallelogram are given by veca=3hati-4hatj-hatk and vecb=2hati+3hatj-6hatk Show that the parallelogram is as rhombus and determine the length of its sides.

The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonals is 2 m?

The length of a side of a square field is 4 m. What will be the altitude of the rhombus, if the area of the rhombus is equal to the square field and one of its diagonals is 2 m?

Show that the diagonals of a rhombus are perpendicular to each other

Show that the diagonals of a rhombus are perpendicular to each other