Text Solution
AI Generated Solution
|
Topper's Solved these Questions
TRIGONOMETRIC FUNCTIONS
RD SHARMA ENGLISH|Exercise All Questions|166 VideosView PlaylistTRIGONOMETRIC RATIOS OF MULTIPLE AND SUBMULTIPLE ANGLES
RD SHARMA ENGLISH|Exercise All Questions|196 VideosView Playlist
Similar Questions
Explore conceptually related problems
RD SHARMA ENGLISH-TRIGONOMETRIC RATIOS OF COMPOUND ANGLES-All Questions
- Prove that: (sin(A+B)+"sin"(A-B))/(cos(A+B)+"cos"(A-B))=t a n A
02:19
|
Play - Prove that: ("sin"(A-B))/(cos A cosB)+(sin(B-C))/(cos B cos C)+("sin"(...
04:17
|
Play - Prove that: ("sin"(A-B))/(sin A sin B)+("sin"(B-C))/(sin B sin C)+("si...
01:56
|
Playing Now - Prove that: sin^2B=sin^2A+sin^2(A-B)-2sin A cos B sin(A-B)
03:28
|
Play - Prove that: cos^2A+cos^2B-2cosA\ cos B cos\ (A+B)=sin^2(A+B)
03:31
|
Play - Prove that: ("tan"(A+B))/("cot"(A-B))=\ (tan^2A-tan^2B)/(1-tan^2Atan^2...
02:42
|
Play - If tan A= xtanB then prove that sin(A-B)/sin(A+B)=(x-1)/(x+1)
04:53
|
Play - If tan(A+B)=x and tan(A-B)=y then find the values of tan2A and tan2B
02:04
|
Play - If cos A+sin B=m and sin A+cos B=n , prove that 2sin(A+B)=m^2+n^2-2.
02:50
|
Play - If tan A+tan B=a and cot A+cot B=b , prove that: cot(A+B)=1/a-1/b
02:31
|
Play - If sin(alpha+beta)=1 and sin(alpha-beta)=1/2, where 0lt=alpha, betalt=...
03:16
|
Play - If alpha, beta are two different values of x lying between 0 and 2pi ...
10:49
|
Play - Prove that (tan^2 (2theta)-tan^2 theta)/(1-tan^2 (2theta) tan^2 theta)...
03:03
|
Play - If sin alpha sin beta-cosalphacosbeta+1=0, then prove that 1+cotalphat...
05:13
|
Play - If t a nalpha=x+1,tanbeta=x-1, show that 2cot(alpha-beta)=x^2dot
03:39
|
Play - Find the maximum and minimum values of 7\ costheta+24\ sintheta
03:14
|
Play - Prove that 5costheta+3cos(theta+pi/3)+3 lies between -4a n d10.
05:41
|
Play - Reduce sqrt(3)sintheta+costheta as a single term consisting sine only
02:42
|
Play - Express: 3costheta-4sintheta\ as c o s i n e of a single expression...
01:38
|
Play - Find the maximum and minimum values of each of the following trigono...
02:04
|
Play