If `alpha+beta-gamma=pi` and `sin^2alpha+sin^2beta-sin^2gamma=lambda sinalpha sinbeta cosgamma,` then write the value of `lambda`

Given alpha+beta-gamma=pi, prove that sin^2alpha+sin^2beta-sin^2gamma=2sinalphasinbetacosgammadot

If sin alpha+ sin beta+ sin gamma=3, then sin^3alpha+sin^3beta+sin^3 gamma=

If alpha+beta+gamma=pi , prove that : cos^2 alpha + cos^2 beta + cos^2 gamma+2cosalpha cosbeta cosgamma=1 .

If cot(alpha+beta)=0\ ,\ then write the value of "sin"(alpha+2beta) .

sinalpha+sinbeta=a ,cosalpha+cosbeta=b=>sin(alpha+beta)

If alphagt0, betagt0, gammagt0, alpha+beta+gamma= pi show that sin^2alpha+sin^2beta-sin^2gamma =

cos alpha sin (beta-gamma) + cos beta sin (gamma-alpha) + cos gamma sin (alpha-beta)=

If 3sinbeta=sin(2alpha+beta) then

If sinalpha+sinbeta=a ,cosalpha+cosbeta=b=>sin(alpha+beta) =

If cosalpha+cosbeta+cosgamma=0 a n d a l so sinalpha+sinbeta+singamma=0, then prove that cos2alpha+cos2beta+cos2gamma =sin2alpha+sin2beta+sin2gamma=0 sin3alpha+sin3beta+sin3gamma=3sin(alpha+beta+gamma) cos3alpha+cos3beta+cos3gamma=3cos(alpha+beta+gamma)