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Prove that cos6A=32cos^6A-48cos^4A+18cos...

Prove that `cos6A=32cos^6A-48cos^4A+18cos^2A-1`

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Prove that: cos6x=32cos^6x-48cos^4x+18cos^2x-1

Prove that : cos 6x=32 cos^6 x -48cos^4 x - 18 cos^2 x -1

Prove that: cos4A=1-8cos^2\ A+8cos^4\ A

cos 6x = 32 cos^6 x- 48 cos^4 x +18 cos^2 x -1

Prove that cos 6x = 32 cos ^(6) x - 48 cos ^(4) x + 18 cos ^(2) x -1.

Prove that: 4"cos"12^0cos48^0cos72^0=cos36^0

Prove that : cos Acos(60-A)cos(60+A)=1/4cos3A

Prove that: cos3A+cos5A+cos7A+cos 15 A=4cos4A cos5A cos6A

Prove that cos6^@ . cos42^@. cos66^@ cos78^@= 1/16

Prove that: (cos2A\ cos3A-cos2Acos7A+cos10 A cos A)/(sin4A\ sin3A-sin2A sin5A+sin4Asin7A )=cot6A\ cot5A

RD SHARMA ENGLISH-TRIGONOMETRIC RATIOS OF MULTIPLE AND SUBMULTIPLE ANGLES-All Questions
  1. Prove that: 8cos^3pi/9-\ 6cospi/9=1.

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  2. Prove that: 108sinpi/(18)-144sin^3pi/(18)=18

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  3. Prove that cos6A=32cos^6A-48cos^4A+18cos^2A-1

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  4. Prove that : cos Acos(60-A)cos(60+A)=1/4cos3A

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  5. Prove that: "s i n A s i n"(60-"A")sin(60+"A")=1/4sin3"A"dot

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  6. Prove that: "sin"20^0"sin"40^0"sin"60^0"sin"80^0=3/(16)

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  7. prove sin(5theta) = 16sin^5(theta)-20sin^3(theta)+5sin(theta)

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  8. Prove that 4(cos ^(3) 10^(@) + sin ^(3) 20^(@)) = 3 ( cos 10^(@) + sin...

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  9. Prove the following identity: cos^3thetasin3theta+sin^3thetacos3theta=...

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  10. Prove the following identity: \ t a nthetat a n(theta+60^0)+t a ntheta...

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  11. Prove that: t a nA+tan(60^0+A)-t a n(60^0-A)=3t a n3A

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  12. Prove that: cotA+"cot"(60^0+A)-cot(60^0-A)=3cot3A

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  13. Prove the following identity: cot A+cot(60^0+A)+cot(120^0+A)=3cot3A

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  14. Prove that: sin^3A+sin^3((2pi)/3+A)+sin^3((4pi)/3+A)=-3/4sin3Adot

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  15. Prove that: |costhetacos(60^0-theta)cos(60^0+theta)lt=1/4 for all valu...

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  16. Prove that: sin(pi/5) sin2pi/5 sin3pi/5 sin4pi/5=5/16

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  17. Prove that cos((2pi)/(15))cos((4pi)/(15))cos((8pi)/(15))cos((16pi)/(15...

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  18. Prove that: sin 12^0sin 48^0sin 54^0=1/8dot

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  19. The value oif the expressin (1+cospi/10)(1+cos(3pi)/10)(1+cos(7pi)/10)...

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  20. Prove that ; 4 sin 27^@=(5+sqrt(5))-sqrt((3-sqrt(5))) we have

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