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RD SHARMA ENGLISH-TRIGONOMETRIC RATIOS OF MULTIPLE AND SUBMULTIPLE ANGLES-All Questions
- Prove that: "sin"20^0"sin"40^0"sin"60^0"sin"80^0=3/(16)
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- prove sin(5theta) = 16sin^5(theta)-20sin^3(theta)+5sin(theta)
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- Prove that 4(cos ^(3) 10^(@) + sin ^(3) 20^(@)) = 3 ( cos 10^(@) + sin...
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- Prove the following identity: cos^3thetasin3theta+sin^3thetacos3theta=...
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- Prove the following identity: \ t a nthetat a n(theta+60^0)+t a ntheta...
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- Prove that: t a nA+tan(60^0+A)-t a n(60^0-A)=3t a n3A
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- Prove that: cotA+"cot"(60^0+A)-cot(60^0-A)=3cot3A
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- Prove the following identity: cot A+cot(60^0+A)+cot(120^0+A)=3cot3A
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- Prove that: sin^3A+sin^3((2pi)/3+A)+sin^3((4pi)/3+A)=-3/4sin3Adot
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- Prove that: |costhetacos(60^0-theta)cos(60^0+theta)lt=1/4 for all valu...
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- Prove that: sin(pi/5) sin2pi/5 sin3pi/5 sin4pi/5=5/16
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- Prove that cos((2pi)/(15))cos((4pi)/(15))cos((8pi)/(15))cos((16pi)/(15...
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- Prove that: sin 12^0sin 48^0sin 54^0=1/8dot
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- The value oif the expressin (1+cospi/10)(1+cos(3pi)/10)(1+cos(7pi)/10)...
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- Prove that ; 4 sin 27^@=(5+sqrt(5))-sqrt((3-sqrt(5))) we have
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- Prove that : sin^2(72^@) - sin^2 (60^@) = (sqrt5 - 1)/8
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- Prove that: sin^2 24^0-sin^2 6^0=(sqrt(5)-1)/8
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- Prove that: sin^2 42^0-cos^2 78^0=(sqrt(5)+1)/8
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- Prove that: cos 78^0cos 42^0cos 36^0=1/8
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- Show that cos(pi/15)cos((2pi)/15)cos((3pi)/15)cos((4pi)/15)cos((5pi)/1...
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