The elevation of a tower at a station A due North of it is `alpha` and at a station B due West of A is `beta` . Prove that height of the tower is `(A B sinalpha sinbeta)/(sin^2alpha-sin^2beta)` .

The elevation of a tower at a station A due north of it is alpha and at a station B due west of A is beta . Prove that the height of the tower is (ABsinalphasinbeta)/(sqrt(sin^2alpha -sin^2beta))

The angle of elevation of a tower PQ at a point A due north of it is 30^(@) and at another point B due east of A is 18^(@) . If AB =a. Then the height of the tower is

The angular elevation of a tower OP at a point A due south of it is 60^@ and at a point B due west of A, the elevation is 30^@ . If AB=3m, the height of the tower is

The angle of elevation of the top of a tower from a point A due south of the tower is alpha and from B due east of tower is beta . If AB=d , show that the height of the tower is d/sqrt(cot^2 alpha+ cot^2 beta) .

The angle of elevation of the top of a tower from a point A due south of the tower is alpha and from B due east of tower is beta . If AB=d , show that the height of the tower is d/sqrt(cot^2 alpha+ cot^2 beta) .

Problem on sine rule Type:-2 (i)The angle of elevation of the top of the tower from a point A due South of the tower is alpha and from B due east of the tower is beta . If AB=d Show that the height of the tower is d/(sqrt(cot^2alpha+cot^2beta)) (ii) A tree stands vertically on a hill side which makes an angle of 15^@ with the horizontal. From a point on the ground 35m down the hill from the base of the tree ; the angle of elevation of the top of the tree is 60^@ .find the height of the tree ?

If 3sinbeta=sin(2alpha+beta) then

Prove that: tan(alpha+beta)tan(alpha-beta)=(sin^2 alpha-sin^2 beta)/(cos^2 alpha-sin^2 beta)

Sum of n terms of the series sinalpha-sin(alpha+beta)+sin(alpha+2beta)-sin(alpha+3beta)+….

Sum of n terms of the series sinalpha-sin(alpha+beta)+sin(alpha+2beta)-sin(alpha+3beta)+….